40x^2=180x

Solution for 40x^2=180x equation:

40x^2=180x

We move all terms to the left:

40x^2-(180x)=0

a = 40; b = -180; c = 0;
Δ = b2-4ac
Δ = -1802-4·40·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-180}{2*40}=\frac{0}{80}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+180}{2*40}=\frac{360}{80}
=4+1/2
$